Re: sscanf behaviour

Hello,

Some problems that I could identify:
.. If you need to read long float, declare your variable as long float,
use 'L' (for double type), not 'l' (for int type);
.. Reason you are not seeing decimals is probably because you did not
set the precision on the output stream

Hence:

#include <iostream>
#include <iomanip>
using namespace std;

int main(int argc, char* argv[])
{
         long float f;
         const char *test = "123456.78";
         sscanf(test, "%9Lf", &f);
         cout << setprecision(9) << f << endl;
         return 0;
}

.. Lastly: sscanf is bad for your mental health. Avoid when possible.

Regards

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